(x^50- y^265465464565465464645665)(x^435 + y^54866545465546464565464565464)(y^5436656544654 - x^543243342343243423)(x^5543353443-y^546465464564543) is one I have made...looks like a chair lol...
But what is the logic behind this ??? I just copy pasted some source codes and experimented, but I don't get the real logic .. something related to 3d Co-ridnate geometry for sure..
does anyone know how i can save widgets to a file and take them to another computer (the internet on that one doesnt work) ? i did this with skins by downloading them in firefox and saving them to a CD but when you try this with widgets it says you need to download opera.
The widget turned out to be quite useful for solving equations numerically (as the root of a function).
At the moment, to look for f(x,y)==0 AND g(x,y)==0, I type "abs(f(x,y))+abs(g(x,y))". Sometimes with an additional sqrt(..), depending on how the neighbourhood of the root is shaped.
To make this more useful, it would be a great help to have colored isolines in the dynamic (wireframe) view, or at least different colors for positive and negative values. It's quite hard to guess from the black lines where the root might be.
By WillSly , # Nov 29, 2008 2:24:21 PM
By Foking , # Nov 26, 2008 2:11:27 PM
-0.5-cos(atan(y/x)*8+sqrt(x*x+y*y)*4)+sign(sin(sqrt(x*x+y*y)*12-1)-0.7)/5
By Zifpro , # Oct 26, 2008 8:36:46 PM
-0.5-cos(atan(y/x)*8+sqrt(x*x+y*y)*4)+sign(sqrt(x*x+y*y)-0.7)/5-sign(sqrt(x*x+y*y)-0.8)/5
By Zifpro , # Oct 26, 2008 8:09:30 PM
By nhatkyngaythangnam , # Sep 22, 2008 5:22:53 AM
By thedalida , # Sep 5, 2008 5:54:39 PM
By SoulStealer2 , # Aug 2, 2008 9:33:36 AM
A precise view of the section of road and cliffside visible from my window.
(2(2abs(cot(x))-((abs(sin(sqr(cot(sqr(y(abs(1/2((((2x-3y+sin(cos(tan(4))))cot(5))^6x-7y)/8^(x-y))))-y))-sqr(cot(50x))-abs(y))-x)+sqr(0.1x-y(sin(4))+1/2)+x(y))^(2(abs(y))(sqr(x))-0.5)-0.5x^y(sin(abs(sqr(x-y)))))/sin(20x)+x(cos(2^y)))+0.5y)(2(2abs(cot(x))-((abs(sin(sqr(cot(sqr(y(abs(1/2((((2x-3y+sin(cos(tan(4))))cot(5))^6x-7y)/8^(x-y))))-y))-sqr(cot(50x))-abs(y))-x)+sqr(0.1x-y(sin(4))+1/2)+x(y))^(2(abs(y))(sqr(x))-0.5)-0.5x^y(sin(abs(sqr(x-y)))))/sin(20x)+x(cos(2^y)))+0.5y))+0.2)(0.0001)
By Candlejack , # Jun 19, 2008 10:34:39 PM
By DIZZLE_SEGAR , # Jan 29, 2008 12:41:00 AM
By ice_syncer , # Dec 9, 2007 6:50:05 PM
2e^-6(x^2+y^2)-SQRT(0.phi)
By ice_syncer , # Dec 9, 2007 6:45:55 PM
1/tan(cos(abs(x)+abs(y)))
By thetechgeek , # Dec 6, 2007 11:51:33 PM
That is a cd (sort of.) Can someone make a penguin?
By Sk8r644 , # Nov 21, 2007 6:27:25 PM
sin(4*sqrt(x^2+y^2))/sqrt(x^2+y^2)
sin(4*sqrt(x^2+y^2))
abs(x^2-y^2)
0.3*sin(4*sqrt(x^2+y^2))*sqrt(x^2+y^2)
x*y(x-y)(x+y)
10*x*y(x-y)(x+y)
(x^2-y^2)
By Lali19871014 , # Oct 21, 2007 9:31:24 PM
By aoe3rules , # Sep 19, 2007 1:01:11 AM
By aoe3rules , # Sep 19, 2007 12:55:41 AM
By firepower22 , # Jul 3, 2007 3:10:17 AM
(tan(5x))+(cos(5y))
(sin(cos(tan(x(y(5))))))
(sin(5(x^2+y^2)))
1-(abs(y)+abs(x))
(sinh(x^2))+(cosh(y^2))-2
(sin(5(x)))+(cos(5(y)))-1
(sin(5(x^2)))+(cos(5(y^2)))-1
(tan(5x))+(cos(5y))+(sin(5x))+(cot(5y))
(x^2+y^2)^5-1
(tan(x^2))/(sec(x^-2))
0-(abs(x^2))+(abs(y^2))
1-((abs(5x))+(abs(5y)))
(sin(5x))(cos(5y))/10
(sin(5x))(cos(5y))/10-1
(sin(5(x^2(y^2))))(cos(5(x^2(y^2))))*3-0.5
1-(x^2*y^2)*4
(tan(cot(sin(cos(y(5))))))+(tan(cot(sin(cos(x(5)))))) (look at top view)
(sin(5(x)))(cos(5(y)))
x^3
(sign(x^3))
(sign(-(x^2*y^2)*1000))
-(sign(-(x^2*y^2)*1000))
1-(1/(15(x^2+y^2)))
(sign(sin(sin(10x)*sin(10y))))
does anyone know how i can save widgets to a file and take them to another computer (the internet on that one doesnt work) ? i did this with skins by downloading them in firefox and saving them to a CD but when you try this with widgets it says you need to download opera.
By aoe3rules , # Jun 28, 2007 6:50:10 PM
At the moment, to look for f(x,y)==0 AND g(x,y)==0, I type "abs(f(x,y))+abs(g(x,y))". Sometimes with an additional sqrt(..), depending on how the neighbourhood of the root is shaped.
To make this more useful, it would be a great help to have colored isolines in the dynamic (wireframe) view, or at least different colors for positive and negative values. It's quite hard to guess from the black lines where the root might be.
By Schneemann , # Jun 11, 2007 2:21:29 AM
By Jadd , # May 29, 2007 4:59:24 PM