But what is the logic behind this ??? I just copy pasted some source codes and experimented, but I don't get the real logic .. something related to 3d Co-ridnate geometry for sure..
does anyone know how i can save widgets to a file and take them to another computer (the internet on that one doesnt work) ? i did this with skins by downloading them in firefox and saving them to a CD but when you try this with widgets it says you need to download opera.
The widget turned out to be quite useful for solving equations numerically (as the root of a function).
At the moment, to look for f(x,y)==0 AND g(x,y)==0, I type "abs(f(x,y))+abs(g(x,y))". Sometimes with an additional sqrt(..), depending on how the neighbourhood of the root is shaped.
To make this more useful, it would be a great help to have colored isolines in the dynamic (wireframe) view, or at least different colors for positive and negative values. It's quite hard to guess from the black lines where the root might be.
"It's amazing, but everytime when the surface changes or when I move it, the old pictures keep "painted" in the window. Is there a way of reparing that?"
waaaayyyy to confusing for me lol you need to make one for idiots like to were you just click and drag it or something lol tell me if yo do ever make one for idiots
It's amazing, but everytime when the surface changes or when I move it, the old pictures keep "painted" in the window. Is there a way of reparing that?
発言者 thedalida, # 2008/09/05 17:54:39
発言者 SoulStealer2, # 2008/08/02 9:33:36
A precise view of the section of road and cliffside visible from my window.
(2(2abs(cot(x))-((abs(sin(sqr(cot(sqr(y(abs(1/2((((2x-3y+sin(cos(tan(4))))cot(5))^6x-7y)/8^(x-y))))-y))-sqr(cot(50x))-abs(y))-x)+sqr(0.1x-y(sin(4))+1/2)+x(y))^(2(abs(y))(sqr(x))-0.5)-0.5x^y(sin(abs(sqr(x-y)))))/sin(20x)+x(cos(2^y)))+0.5y)(2(2abs(cot(x))-((abs(sin(sqr(cot(sqr(y(abs(1/2((((2x-3y+sin(cos(tan(4))))cot(5))^6x-7y)/8^(x-y))))-y))-sqr(cot(50x))-abs(y))-x)+sqr(0.1x-y(sin(4))+1/2)+x(y))^(2(abs(y))(sqr(x))-0.5)-0.5x^y(sin(abs(sqr(x-y)))))/sin(20x)+x(cos(2^y)))+0.5y))+0.2)(0.0001)
発言者 Candlejack, # 2008/06/19 22:34:39
発言者 DIZZLE_SEGAR, # 2008/01/29 0:41:00
発言者 ice_syncer, # 2007/12/09 18:50:05
2e^-6(x^2+y^2)-SQRT(0.phi)
発言者 ice_syncer, # 2007/12/09 18:45:55
1/tan(cos(abs(x)+abs(y)))
発言者 thetechgeek, # 2007/12/06 23:51:33
That is a cd (sort of.) Can someone make a penguin?
発言者 Sk8r644, # 2007/11/21 18:27:25
sin(4*sqrt(x^2+y^2))/sqrt(x^2+y^2)
sin(4*sqrt(x^2+y^2))
abs(x^2-y^2)
0.3*sin(4*sqrt(x^2+y^2))*sqrt(x^2+y^2)
x*y(x-y)(x+y)
10*x*y(x-y)(x+y)
(x^2-y^2)
発言者 Lali19871014, # 2007/10/21 21:31:24
発言者 aoe3rules, # 2007/09/19 1:01:11
発言者 aoe3rules, # 2007/09/19 0:55:41
発言者 firepower22, # 2007/07/03 3:10:17
(tan(5x))+(cos(5y))
(sin(cos(tan(x(y(5))))))
(sin(5(x^2+y^2)))
1-(abs(y)+abs(x))
(sinh(x^2))+(cosh(y^2))-2
(sin(5(x)))+(cos(5(y)))-1
(sin(5(x^2)))+(cos(5(y^2)))-1
(tan(5x))+(cos(5y))+(sin(5x))+(cot(5y))
(x^2+y^2)^5-1
(tan(x^2))/(sec(x^-2))
0-(abs(x^2))+(abs(y^2))
1-((abs(5x))+(abs(5y)))
(sin(5x))(cos(5y))/10
(sin(5x))(cos(5y))/10-1
(sin(5(x^2(y^2))))(cos(5(x^2(y^2))))*3-0.5
1-(x^2*y^2)*4
(tan(cot(sin(cos(y(5))))))+(tan(cot(sin(cos(x(5)))))) (look at top view)
(sin(5(x)))(cos(5(y)))
x^3
(sign(x^3))
(sign(-(x^2*y^2)*1000))
-(sign(-(x^2*y^2)*1000))
1-(1/(15(x^2+y^2)))
(sign(sin(sin(10x)*sin(10y))))
does anyone know how i can save widgets to a file and take them to another computer (the internet on that one doesnt work) ? i did this with skins by downloading them in firefox and saving them to a CD but when you try this with widgets it says you need to download opera.
発言者 aoe3rules, # 2007/06/28 18:50:10
At the moment, to look for f(x,y)==0 AND g(x,y)==0, I type "abs(f(x,y))+abs(g(x,y))". Sometimes with an additional sqrt(..), depending on how the neighbourhood of the root is shaped.
To make this more useful, it would be a great help to have colored isolines in the dynamic (wireframe) view, or at least different colors for positive and negative values. It's quite hard to guess from the black lines where the root might be.
発言者 Schneemann, # 2007/06/11 2:21:29
発言者 Jadd, # 2007/05/29 16:59:24
発言者 Archonic, # 2007/05/23 18:37:37
Regards,
Benjamin
発言者 Benjamin Joffe, # 2007/05/07 18:50:58
SAME PROBLEM HERE!
発言者 miron22, # 2007/05/03 18:19:43
発言者 mikeoo92, # 2007/04/22 20:27:10
発言者 Reggiostar, # 2007/04/21 15:40:39